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Certification with an NP Oracle

Talkat ITCS 2023 · 2023-01-10..01-13· [computer-vision]
name:Guy Blanc
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Checking a claimed certificate is coNP-complete, and under P ≠ NP no algorithm finds a certificate of size φ(k) for any rapidly growing φ. With access to an NP oracle the problem admits a BPP^NP algorithm that outputs a poly(k)-size certificate when f has certificate complexity ≤ k, while the instance-wise problem is NP^NP-hard to approximate: it is hard to distinguish a yes case with a size-k certificate from a no case where every certificate has size ≥ k·n^{1−ε}.

AI-written summary · about

  1. 0:00Intro
  2. 0:16Explaining the behavior of black boxes
  3. 1:46Certificates as explanations
  4. 3:14Certificates in theory and in practice
  5. 6:54Given intractability, what to do?
  6. 7:36Why is certification "easy" for monotone f?
  7. 12:08The algorithmic problem we consider (revised)
  8. 12:32Result 1: Certification in BPPNP
  9. 14:02Result 2: Instance-wise certification is NPNP-hard
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